converter decimal, biner, oktal

Exercise 1

A.      Convert into decimal

1.       (110010101) = (1x2⁵)+

(1x2⁸)+(1x2⁷)+(0x2⁶)+(0x2⁵)+(1x2⁴)+(0x2³)+(1x2²)+(0x2¹ )+(1x2⁰)= (256) + (128) + (0) +(0) + (16) + (0) + (4) + (0) + (10) =(405)₁₀

2.       (001000100)₂=(0x2⁸)+

(0x2⁸)+(0x2⁷)+(1x2⁶)+(0+2⁵)+(0+2⁴)+(0x2³)+(1x2²)+(0x2¹)+(0x2⁰) = (0) + (0) + (64) + (0) + (0) + (0) + (4)  + (0) + (0) = (68)₁₀

3.       (4562)₈=(4x8³)+(5x8²)+(6x8¹)+(2x8⁰) = (2048) + (320) + (48) + (2) = (2418)₁₀

4.       (361)₈=(3x8²)+(6x8¹)+(1x8⁰) =  (192) + (48) + (1) = (241)₁₀

5.       (34510)₁₆=(3x16⁴)x(4x16³)+(5x16²)+(1x16¹)+(0x16⁰) = (196608) + (16384) + (1280) + (16) + (0) = (214288)₁₀

6.       (A134)₁₆=(10x16³)+(1x16²)+(3x16¹)+(4x16⁰) = (40960) + (256) + (48) + (4) = (41264)₁₀

Exercise 2

Convert the decimal number 349 and 1234 into

1.       Binary

349=      2l349

                2l174 – 1

                2l87 – 0

                2l43 – 1

                2l21 – 1

                2l10 – 1

                2l5 – 0

                2l2 – 1

                2l1 – 0

                   0 – 1

Binary=101011101

1234=    2l1234

                2l617 – 0

                2l308 – 1

                2l154 – 0

                2l77 – 0

                2l38 – 1

                2l19 – 0

                2l9 – 1

                2l4 – 1

                2l2 – 0

                2l1 – 0

                  0 – 1

Binary= 10011010010

2.       Octal

349=      8l349

                8l43 – 5

                8l5 – 3

                   0 – 5

Octl = 535

1234 =   8l1234

                8l154 – 2

                8l19 – 2

                8l2 – 3

                8l0 – 2

Octal = 2322

3.       Haxedecimal

349=      16l349

                16l21 – 13

                16l1 – 5

                     0 – 1

                Hexadecimal= 15 D

1234 =   17l1234

                17l77 – 2

                17l4 -13

                     0l4

haxedecimal = 4D2

               

Exercise 3

Convert the following numbers into binary

1.       (3241)₁₀

Decimal to binary

3241=            2l3241

                        2l1620 – 1

                        2l810 - 0

                        2l405 -  0

                        2l202 - 1

                        2l101 - 0

                        2l50 - 1

                        2l25 - 0

                        2l12 - 1

                        2l6 - 0

                        2l3 – 0

                        2l1 – 1

                           0 – 1

Binary= 110010101001

                                       

2.       (75036)₈

Octal to binary

Octal              7                              5             0             3             6

Binary           111                         101         000         011         110

Jadi (75036)₈ = (111101000011110)

3.       (5C09F)₁₆

Hexademical to binary

Hexademical              5                              C                             0                              9                              F

Binary                           0101                       1100                       0000                       1001                       1111

Jadi (5C09F)₁₆ = (1011100000010011111)₂

Exercise 4

Convert the binary number  11011001001 into:

1.       Decimal

(1x2¹⁰)+(1x2⁹)+(0x2⁸)+(1x2⁷)+(1x2⁶)+(0x2⁵)+(0x2⁴)+(1x2³)+(0x2²)+(0x2¹)+(1x2⁰)= (1024) + ( 512) + (0) + (128) + (64) + (0) + (0) + (8) + (0) + (0) + (1)= (1737)₁₀

2.       Octal

Binary       011                         011                         001                         001

Octal          3                              3                              1                              1

Jadi (011011001001)₂ =(3311)₈

3.       Hexadecimal

Binary                       0110                       1100                       1001

Hexadecimal          6                              C                             9

Jadi (011011001001)₂ =(6C9)₈

               

               

               

       

               

Chapter 2

Exercise 1

Fine the sum of the binary numbers:

1.       110011 and 11010

1              1              0              0              1              1

                1              1              0              1              0              +

            10        0          1          1          0          1

Jadi hasilnya = 1001101

2.       111100 and 110001

1          1          1          1          0          0

1          1          0          0          0          1          +

11        0          1          1          0          1

Jadi hasilnya adalah = 1101101

3.       10110011 and 11100010

1          0          1          1          0          0          1          1

1          1          1          0          0          0          1          0          +

11        0          0          1          0          1          0          1

Jadi hasilnya adalah = 110010101